madisong57 madisong57

03-03-2016
Physics

Answered

a weightlifter lifts a 1000 newton barbell above his head from the floor to a height of 2.5 meters. he holds the barbell there for 5 seconds. how much work does he do during the 5 second interval?

Verified Answer :

olemakpadu olemakpadu

03-03-2016

Work done = Potential Energy = (mg)h

   mg = weight of the ball

   = 1000 N * 2.5 m = 2500 Joules.

The work done during the 5 second is 2500 Joules.

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