Verified Answer :

mashenka

Assuming this is the equation you want to operate on:
\(v^{2} = (v_0)^{2} + 2\cdot a \cdot \Deltax\)
\(2\cdot a \cdot \Delta x = v^{2} - (v_0)^{2}\)
\(a = \frac{v^{2} - (v_0)^{2}}{2\cdot \Delta x}\)
Before final operation we have to assume that x is not equal to 0. :)

konrad509

\(V^2=V_0^2+2a\Delta x\\ 2a\Delta x=V^2-V_0^2\\ a=\frac{V^2-V_0^2}{2\Delta x}\)

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