Verified Answer :

square root both sides and don't forget to get the positive and negative roots
x=+/-\(\sqrt{160}\)

\(\sqrt{160}\)=\(\sqrt{16}\) times \(\sqrt{10}\)

\(\sqrt{16}\)=+/-4
 
answer is
+/-4\(\sqrt{10}\)

answer is b




\(x^2 = 160 \\ \\ x = \pm \sqrt{160} \\ \\ x = \pm 4 \sqrt{10} \\ \\\)

The final result is: x = ±4 √10 or B.