Verified Answer :

Formula for distance between two points:

d  = √((x₂-x₁)² + (y₂-y₁)²)

Let point 1 be (-3, 11) and point 2 be (5, 5)

Therefore x₁ = -3, y₁ = 11, x₂ =5, y₂ = 5, and substituting in the formula above.

d = √((x₂-x₁)² + (y₂-y₁)²)

   = √((5- -3)² + (5-11)²)

   = √((5+3)² + (5-11)²)

   = √((8)² + (-6)²)          8² = 88 = 64, (-6)² = -6-6 = 36

   = √(64 + 36)

  = √(100)

  = 10

Distance = 10 units.

Answer:

Formula for distance between two points:


d  = √((x₂-x₁)² + (y₂-y₁)²)


Let point 1 be (-3, 11) and point 2 be (5, 5)


Therefore x₁ = -3, y₁ = 11, x₂ =5, y₂ = 5, and substituting in the formula above.


d = √((x₂-x₁)² + (y₂-y₁)²)


  = √((5- -3)² + (5-11)²)


  = √((5+3)² + (5-11)²)


  = √((8)² + (-6)²)          8² = 88 = 64, (-6)² = -6-6 = 36


  = √(64 + 36)


 = √(100)


 = 10


Distance = 10 units.