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  • 01-03-2016
  • Mathematics
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Solve the equation by finding square roots. x^2-16=0

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  • 01-03-2016

\(x^2-16=0 \\ \\ x^2 = 16 \\ \\ x = \pm \sqrt{16} \\ \\ x = \pm 4 \\ \\\)

The final result is: x = ±4

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