-2 (m+n-4)+5 (-2m+2n)+n (m+4n-5)
so if you want to addwe distributea(b+c)=ab+ac so -2(m+n-4)=-2m-2n+85(-2m+2n)=-10m+10nn(m+4n-5)=mn+4n^2-5nso total we ahve-2m-2n+8-10m+10n+mn+4n^2-5ngroup like terms4n^2+-2m-10m-2n+10n-5n+mn+8add like temrs4n^2-12m+3n+mn+8
