Solutions
\(a^{2}\) + \(b^{2}\) = \(c^{2}\)
10 is \(a^{2}\) and 14 is \(b^{2}\)
To find \(c^{2}\) you have to add \(a^{2}\) + \(b^{2}\).
Calculations
\(10^{2}\) + \(14^{2}\) = \(c^{2}\)
\(10^{2}\) = 10 x 10
\(10^{2}\) = 100
\(14^{2}\) = 14 x 14
\(14^{2}\) = 196
Since \(a^{2}\) + \(b^{2}\) = \(c^{2}\) you have to add \(10^{2}\) and \(14^{2}\) .
100 + 196 = 296
To find the hypotenuse you have to square root 296.
\(\sqrt{269}\)
= 17.2
17.2 is the hypotenuse or \(c^{2}\)
