The coefficients a, b & c come out to be 48,144, and -84 respectively.
The given expression is:
\((4x-2)*6(2x+7)\)
We can rewrite it as
\(6(4x-2)*(2x+7)\)
taking 2 as common from \(4x-2\)
\(12(2x-1)*(2x+7)\)
Multiply \((2x-1)\) with \((2x+7)\)
\(12(4x^{2} +14x-2x-7)\)
\(12(4x^{2} +12x-7)\)
\(48x^{2} +144x-84\)
What is the general form of a quadratic expression?
The general form of a quadratic expression is \(ax^{2} +bx+c=0\) with \(a
eq 0\).
If we compare \(48x^{2} +144x-84\) with the general form of a quadratic equation
\(a=48\\b=144\\c=-84\)
Hence, the coefficients a, b & c come out to be 48,144, and -84 respectively.
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