solve 3x^2+2x-8=0, using an algebraic method.
you should factor this question so you will have: (3x - 4)(x +2) so now you have:(3x-4)(x+2)=0 ⇒ 3x -4 =0 and x+2 =0 3x-4=0 ⇒ 3x = 4 ⇒ x = 4/3 and x + 2 =0 ⇒ x = -2 :)))so you have two x x = -2, 4/3 :)))i hope this is helpful have a nice day
