Verified Answer :

Given the points, when point A, B, C, D are plotted, and connect AB and CD to form a segment, they are not neither parallel nor perpendicular.

we have that

\(A(0, 0)\\B(e, f)\\ C(0, e)\\D(f, 0)\)


we know that

If two lines are parallel

then

their slopes are equals

and

if two lines are perpendicular

then

the product of their slopes is equal to \(-1\)


step 1

find the slope of the line segment AB

\(m=\frac{(y2-y1)}{(x2-x1)}\)

\(mAB=\frac{(f-0)}{(e-0)}\)

\(mAB=\frac{(f)}{(e)}\)


step 2

find the slope of the line segment CD

\(m=\frac{(y2-y1)}{(x2-x1)}\)

\(mCD=\frac{(0-e)}{(f-0)}\)

\(mCD=\frac{(-e)}{(f)}\)


\(mAB*mCD=(\frac{f}{e} )*(\frac{-e}{f} )\\ =-1\)

therefore


the answer is

Line segments AB and CD are perpendicular