Verified Answer :

Answer : The correct option is, 12.40

Explanation : Given,

Concentration of \(OH^-\) ion = 0.025 M

First we have to calculate the pOH.

\(pOH=-\log [OH^-]\)

\(pOH=-\log (0.025)\)

\(pOH=1.6\)

Now we have to calculate the pH.

\(pH+pOH=14\\\\pH=14-pOH\\\\pH=14-1.6=12.40\)

Therefore, the pH of a solution is, 12.40

Answer:

D) 12.40

Explanation:

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