What is the mass in grams of 1.73 mol Cal2
First you find the molar mass of the compound.
1Ca: 40.078g/mol
2I: 126.904g/mol
CaI₂:293.886g/mol
Now you multiply the mols by the molar mass:
1.73mol CaI₂ₓ 293.886g/1mol ≈ 508g CaI₂
Explanation:
It is known that number of moles equal mass divided by molar mass.
Mathematically, No. of moles = \(\frac{mass}{\text{molar mass}}\)
It is known that molar mass of \(CaI_{2}\) is 293.887 g/mol and number of moles given are 1.73 mol.
Hence, calculate the mass as follows.
No. of moles = \(\frac{mass}{\text{molar mass}}\)
1.73 mol = \(\frac{mass}{293.887 g/mol}\)
mass = 508.424 g
Thus, we can conclude that mass of \(CaI_{2}\) is 508.424 g.