h n I g. x V I .. Bi h H- . .
\(x^{2} =169\\\\\sqrt{x^2} =\pm\sqrt{169}\\\\x =\pm \sqrt{169}\\\\x =\pm 13\\\\\boxed{\bf{x = 13}}\\\boxed{\bf{x=-13}}\)
x^2= 169⇒ x^2 -169= 0⇒ x^2- 13^2= 0⇒ (x-13)(x+13)= 0⇒ x-13= 0 or x+ 13= 0⇒ x= 13 or x= -13The correct answer is 13 and -13.
