\(3 y + 4 x \ \textless \ 12\)
Subtract 4 x from both sides
\(3y+4x-4x \ \textless \ 12-4x\)\(3y\ \textless \ 12 - 4x\)
Divide both sides by 3 :
\(\frac{3y}{3} \ \textless \ \frac{12-4x}{3}\)
\(y\ \textless \ \frac{12-4x}{3}\)
Image attached
hope this helps!
