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∆ABC is translated 6 units up and 3 units left to create ∆A'B'C'. If vertex A is at (-1, 2) and vertex B is at (1, 5), then vertex A' is at

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W0lf93

So we want to know the new coordinates for the vertex A'(x,y) if we know that the vertex A is at A(-1,2) and vertex B is at B(1,5) and that the triangle ABC is translated 6 units up and 3 units left. So the method is simply to add units 6 to x and 3 to y of A to get A'. Going left means we need to go to negative x direction and going up means we need to go to positive y direction. So: A'(-1-3,2+6) and that is: A'(-4,8).

JeanaShupp

Answer: (-4,8)

Step-by-step explanation:

The translation rule for translating a point h units left  is given by :-

\((x,y)\to (x-h,k)\)

The translation rule for translating a point k units up is given by :-

\((x,y)\to (x,y+k)\)

Given : ∆ABC is translated 6 units up and 3 units left to create ∆A'B'C'. If vertex A is at (-1, 2) and vertex B is at (1, 5).

Then, the vertex A'  will be :-

\(A(-1,2)\to(-1-3,\ 2+6)=(-4,\ 8)\)

Hence, the vertex A' is at (-4,8).

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