What is the total power in a circuit if the resistance is 800 and the voltage is 60 VDC?

A4.5 W
B13.33 W
C120 W
D48 W

User:

A circuit contains six 20 resistors connected in series. What is the total circuit resistance?

A60
B3.33
C6
D120

User:

What circuit quantity is measured by connecting a meter's test leads in series with an energized component?

AVoltage
BCurrent
CPower
DResistance

1.) Power, P = V²/R = 800²/45 = 4.5 W (A).

2.) Six Resistors in Series.
R = R1 + R2 + R3 + R4 + R5 + R6, Since R is the same, R = 20

R total = 6*20 = 120 (D)

3.) It is the current. Series connection is to evaluate current. (B)

Answer Link

skyluke89 skyluke89 · Answer 2 · 2019-01-04T11:17:46-05:00

1. A. 4.5 W

The power in a circuit is given by:

\(P=\frac{V^2}{R}\)

where V is the voltage and R is the resistance.

In this circuit, we have:

\(V=60 V\) is the voltage

\(R=800 \Omega\) is the resistance

Therefore, the power in the circuit is

\(P=\frac{(60 V)^2}{800 \Omega}=4.5 W\)

2. D. \(120 \Omega\)

The total resistance of resistors connected in series is the sum of the individual resistances:

\(R_T = R_1 +R_2 +R_3 +...\)

In this case, we have 6 identical resistors with same resistance \(R=20 \Omega\). Therefore, the total resistance will be

\(R_T = 20 \Omega +20 \Omega +20 \Omega +20 \Omega +20 \Omega +20 \Omega =120 \Omega\)

3. B. Current

An ammeter is a device which is put in series with another component of the circuit, in order to measure the current through it. In fact, in a circuit, components which are connected in series have the same current flowing through them: therefore, the reading of the current in the ammeter will corresponds to the same current which is flowing to the other component.