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An object is located 51 millimeters from a diverging lens. The object has a height of 13 millimeters and the image height is 3.5 millimeters. How far in front of the lens is the image located?

A.51 millimeters

B.1.12 millimeters

C.13.7 millimeters

D.189 millimeters

Verified Answer :

RaeYosry

you would get 13.7 
lets say mi/mo= hi/ho
mi/51mm=3.5mm/13mm
by solving it you will C.13.7mm

hope this helps 

Samaruh

when the distance is divided by the height of an object is a constant. Therefore (x/3.5=51/13) yields the answer as 13.7.


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