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An electric heating element is connected to a 110 V circuit and a current of 3.2 A is flowing through the element. How much energy is used up during a period of 5 hours by the element

Verified Answer :

olemakpadu

Energy, E is given by =  IVt

Where E is Energy in Juoles.
I is Current in Amperes,
t is time in seconds,

I = 3.2 A,    V = 110 V,    t = 5 hours = 5 3600 seconds.  1 hour = 3600s

E =  3.2 110 5 3600

E = 6 336 000 Juoles

E = 6.336 * 10^6 J  =  6.336 MJ

PutereDinu

\(V=110 \ V \\ I=3,2 \ A \\ t=5 \ h=18 \ 000 \ s \\ \boxed{E-?} \\ \bold{Solving:} \\ \boxed{E=V \cdot t \cdot I} \\ E=110 \ V \cdot 3,2 \ A \cdot 18 \ 000 \ s \\ \Rightarrow \boxed{E=6 \ 336 \ 000 \ J}\)

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