Find the 37th term of the sequence 2, 5, 8, 11, 14, . . .
Answer: 110
Use the formula \(a_n=a_1+d(n-1)\)
The sequence is \(a_n=3n-1\)
Simply plug in 37 into the formula and you get 110.
Hope this helps!!!
\(Sofia\)
The 37th term of the sequence is 110.
An arithmetic sequence is defined as an arrangement of numbers which is a particular order.
The formula to find the general term of an arithmetic sequence is,
Tₙ = a₁ + (n-1)d
In arithmetic, sequence d represents the common difference.
Where aₙ is the nth term of the sequence and a₁ is the first term.
Given that the sequence as 2, 5, 8, 11, 14, . . .
Here the first term is 2.
a₁ = 2
So, the common difference = 5 - 2 = 3
d = 3
To determine the 37th term of the sequence
Tₙ = a₁ + (n-1)d
Substitute the values of n = 37, a₁ = 2, and d = 3 in the formula of arithmetic sequence
T₃₇ = 2 + (37-1)3
T₃₇ = 2 + (36)3
T₃₇ = 2 + 108
T₃₇ = 110
Hence, the 37th term of the sequence is 110.
Learn more about arithmetic sequence here:
brainly.com/question/21961097
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