Select the correct answer.
What is the solution to this equation?
$\log _6 x+\log _6 3=\log _6(x+1)$
A$x=\frac{3}{2}$
B$x=1$
C$x=\frac{1}{2}$
D$x=\frac{1}{3}$
What is the solution to this equation?
$\log _6 x+\log _6 3=\log _6(x+1)$
A$x=\frac{3}{2}$
B$x=1$
C$x=\frac{1}{2}$
D$x=\frac{1}{3}$