What is the true solution to the equation?
$\ln e^{\ln x}+\ln e^{\ln x^2}=2 \ln 8$
A$x=8$
B$x=64$
C$x=2$
D$x=4$
$\ln e^{\ln x}+\ln e^{\ln x^2}=2 \ln 8$
A$x=8$
B$x=64$
C$x=2$
D$x=4$