Identify the quotient and the remainder.
$\left(24 x^3-14 x^2+20 x+6
ight) \div\left(4 x^2-3 x+5
ight)=Q+\frac{R}{4 x^2-3 x+5}$
$Q=\square$
$R=\square$
$\left(24 x^3-14 x^2+20 x+6
ight) \div\left(4 x^2-3 x+5
ight)=Q+\frac{R}{4 x^2-3 x+5}$
$Q=\square$
$R=\square$