Type the correct answer in each box. Use numerals instead of words.
The zeros of the function $f(x)=-(x+1)(x-3)(x+2)$ are $-1, 3$, and [blank], and the $y$-intercept of the function is located at $(0, \text{[blank]})$.
The zeros of the function $f(x)=-(x+1)(x-3)(x+2)$ are $-1, 3$, and [blank], and the $y$-intercept of the function is located at $(0, \text{[blank]})$.