Find the values for the variables that show how to subtract the rational expressions correctly:
$\begin{aligned}
\frac{2}{x^2-36}-\frac{1}{x^2+6 x} & =\frac{2}{(x+6)(x-6)}-\frac{1}{x(x+a)} \\
& =\frac{b x}{(x+6)(x-6) x}-\frac{x-c}{(x+6)(x-6) x} \\
& =\frac{d x-x+e}{(x+6)(x-6) x} \\
& =\frac{x+f}{(x+6)(x-6) x} \\
& =\frac{g}{x(x-6)}
\end{aligned}$
$\begin{aligned}
\frac{2}{x^2-36}-\frac{1}{x^2+6 x} & =\frac{2}{(x+6)(x-6)}-\frac{1}{x(x+a)} \\
& =\frac{b x}{(x+6)(x-6) x}-\frac{x-c}{(x+6)(x-6) x} \\
& =\frac{d x-x+e}{(x+6)(x-6) x} \\
& =\frac{x+f}{(x+6)(x-6) x} \\
& =\frac{g}{x(x-6)}
\end{aligned}$