Consider the two-way table below.
C D Total
A15 21 36
B9 25 34
Total24 46 70
Find $P(B \mid C)$.
A$P(B \mid C)=\frac{9}{34}=0.26$
B$P(B \mid C)=\frac{9}{24}=0.38$
C$P(B \mid C)=\frac{9}{70}=0.13$
D$P(B \mid C)=\frac{9}{58}=0.16$
| C | D | Total | |
A | 15 | 21 | 36 |
B | 9 | 25 | 34 |
Total | 24 | 46 | 70 |
A$P(B \mid C)=\frac{9}{34}=0.26$
B$P(B \mid C)=\frac{9}{24}=0.38$
C$P(B \mid C)=\frac{9}{70}=0.13$
D$P(B \mid C)=\frac{9}{58}=0.16$