The $y$-intercept is $(0,-5)$. The graph of $5x - 3y = 15$ passes through the point $(0,-5)$.

Now, to graph the equation, plot the intercepts. Plot the $x$-intercept, $(3,0)$.

Plot the $y$-intercept, $(0,-5)$.

Now, to complete the graph, draw a straight line through the points, as shown.

Always remember to plot a third point to make sure the graph is correct. For the checkpoint, let $x = 6$ and find the corresponding value for $y$.



$\begin{aligned}

5x - 3y &= 15 \\

5(6) - 3y &= 15 & \text{Let } x=6. \\

30 - 3y &= 15 & \text{Simplify.} \\

-3y &= -15 & \text{Subtract.} \\

y &= \square & \text{Divide.}

\end{aligned}$