The formula for the area of a trapezoid is $A=\frac{1}{2}\left(b_1+b_2\right) h$. When this equation is solved for $b_1$, one equation is $b_1=\frac{2 A}{h}-b_2$. Which of the following is an equivalent equation to find $b_1$?
A$b_1=\frac{2 A-b_2 h}{h}$
B$b_1=2 A-b_2 h$
C$b_1=\frac{h}{2 A-b_2 h}$
D$b_1=h\left(2 A-b_2 h\right)$
A$b_1=\frac{2 A-b_2 h}{h}$
B$b_1=2 A-b_2 h$
C$b_1=\frac{h}{2 A-b_2 h}$
D$b_1=h\left(2 A-b_2 h\right)$