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prahladshyamgupta108 prahladshyamgupta108
  • 03-11-2026
  • Chemistry
Answered

237.5 g of titanium chloride is added to 4.50 mol of sodium.



$TiCl_4+4 Na \longrightarrow Ti+4 NaCl$



Relative formula mass $\left(M_r\right): TiCl _4=190$


ACalculate the moles of titanium chloride in 237.5 g.


BHence, write the name of the limiting reactant.

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