A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm, what is the new volume of the balloon in the hot room?
Use $\frac{V_1}{T_1}=\frac{V_2}{T_2}$.
A2.19 L
B3.33 L
C3.68 L
D5.60 L
Use $\frac{V_1}{T_1}=\frac{V_2}{T_2}$.
A2.19 L
B3.33 L
C3.68 L
D5.60 L