Which inequality is equivalent to $3+\frac{4}{x} \geq \frac{x+2}{x}$?
A$\frac{2 x+2}{x} \geq 0$
B$\frac{2 x+6}{x} \geq 0$
C$\frac{-x+5}{x} \geq 0$
D$\frac{-x+9}{x} \geq 0$
A$\frac{2 x+2}{x} \geq 0$
B$\frac{2 x+6}{x} \geq 0$
C$\frac{-x+5}{x} \geq 0$
D$\frac{-x+9}{x} \geq 0$