Tran solves the system of equations by forming a matrix equation.
$\begin{array}{c}
2 x-3 y=19 \\
x+2 y=-1
\end{array}$
He multiplies the left side of the coefficient matrix by the inverse matrix.
How does he proceed to the solution?
$\left[\begin{array}{cc}
2 & -3 \\
1 & 2
\end{array}\right]^{-1}\left[\begin{array}{cc}
2 & -3 \\
1 & 2
\end{array}\right] \bullet\left[\begin{array}{l}
x \\
y
\end{array}\right]=$
Complete Tran's process.
$\begin{array}{c}
2 x-3 y=19 \\
x+2 y=-1
\end{array}$
He multiplies the left side of the coefficient matrix by the inverse matrix.
How does he proceed to the solution?
$\left[\begin{array}{cc}
2 & -3 \\
1 & 2
\end{array}\right]^{-1}\left[\begin{array}{cc}
2 & -3 \\
1 & 2
\end{array}\right] \bullet\left[\begin{array}{l}
x \\
y
\end{array}\right]=$
Complete Tran's process.