What value of $c$ makes the equation true? Assume $x>0$ and $y>0$.
$\sqrt[3]{\frac{x^3}{c y^4}}=\frac{x}{4 y(\sqrt[3]{y})}$
A$c=12$
B$c=16$
C$c=64$
D$c=81$
$\sqrt[3]{\frac{x^3}{c y^4}}=\frac{x}{4 y(\sqrt[3]{y})}$
A$c=12$
B$c=16$
C$c=64$
D$c=81$