Suppose that you want to find the molarity of a solution that contains 15.0 g of KCl in 150.0 mL of solution. (The molar mass of KCl is $74.45 g / mol$.)



Calculate the number of moles of KCl:

$\frac{A}{B}=C$



A: □

B: □

C: □



Calculate the molarity of the solution:

$\frac{0.201 mol}{D} \times \frac{1000 mL}{1 L}=E$



D: □

E: □