What is the molarity of a solution of $Cu _2 SO _4$ if 250.0 mL of solution contains 14.1 g of $Cu _2 SO _4$? Assume the molar mass of $Cu _2 SO _4$ is $223.2 g / mol$.



Calculate the number of moles of $Cu _2 SO _4$ present:

$\frac{A}{m \times 2 \pi / mol}=B$



A: □

B: □



Calculate the molarity of the solution:

$\frac{\operatorname{losen} C}{C} \times \frac{T}{1 L}=D$



C: □

D: □