What is the solution to the equation $\frac{m}{m+4}+\frac{4}{4-m}=\frac{m^2}{m^2-16}$ ?
A$m=-4$
B$m=-2$
C$m=2$
D$m=4$
A$m=-4$
B$m=-2$
C$m=2$
D$m=4$