What is the solution for the equation $\frac{5}{3 b^3-2 b^2-5}=\frac{2}{b^3-2}$ ?
A$b=-4$ and $b=0$
B$b=-4$
C$b=0$ and $b=4$
D$b=4$
A$b=-4$ and $b=0$
B$b=-4$
C$b=0$ and $b=4$
D$b=4$