Which explains how to find the quotient of the given division?
$\frac{-3 \frac{1}{3}}{\frac{4}{9}}$
AWrite $-3 \frac{1}{3}$ as $-\frac{10}{3}$, and find the reciprocal of $\frac{4}{9}$ as $\frac{9}{4}$. Then, rewrite $\frac{-3 \frac{1}{3}}{\frac{4}{9}}$ as $-\frac{10}{3} \times \frac{9}{4}$.
BWrite $-3 \frac{1}{3}$ as $-\frac{10}{3}$. Then, rewrite $\frac{-3 \frac{1}{3}}{\frac{4}{9}}$ as $-\frac{10}{3} \times \frac{4}{9}$.
$\frac{-3 \frac{1}{3}}{\frac{4}{9}}$
AWrite $-3 \frac{1}{3}$ as $-\frac{10}{3}$, and find the reciprocal of $\frac{4}{9}$ as $\frac{9}{4}$. Then, rewrite $\frac{-3 \frac{1}{3}}{\frac{4}{9}}$ as $-\frac{10}{3} \times \frac{9}{4}$.
BWrite $-3 \frac{1}{3}$ as $-\frac{10}{3}$. Then, rewrite $\frac{-3 \frac{1}{3}}{\frac{4}{9}}$ as $-\frac{10}{3} \times \frac{4}{9}$.