A student solved $-4(2 x-3)+10 x \leq 20$. After combining $-8 x$ and $10 x$ on the same side, they flipped the inequality symbol, ending up with a final answer of $x \leq-16$.
What mistake did the student make, and what is the correct solution set for $-4(2 x-3)+10 x \leq 20$?
What mistake did the student make, and what is the correct solution set for $-4(2 x-3)+10 x \leq 20$?