The Hamiltonian for a spinless particle is given by H = 5/ℏ ₓ – /ℏ² (²ᵧ + ²), where is a positive constant. If the orbital angular momentum of the particle is given to be =3, then the ground state energy is
(A) -18
(B) -16
(C) -20
(D) -14
(A) -18
(B) -16
(C) -20
(D) -14