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aliay6299 aliay6299
  • 04-06-2024
  • Physics
Answered

A particle's velocity in meters per second along the x-axis is described by v(x) = Ax + Bx², where the position x is in meters. The values of the constants are A = 5.51, and B = -3.4. What is the acceleration, in meters per square second, of the particle at the location you found in part b?

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